The standard (reduction) electrode potentials for metal-metal ion (M/M2+) electrodes P, Q, R and S are respectively -0.44 V, +0.34 V, -0.76 V and -0.25 V The increasing order of their reducing capacities is

Question

The standard (reduction) electrode potentials for metal-metal ion (M/M2+) electrodes P, Q, R and S are respectively -0.44 V, +0.34 V, -0.76 V and -0.25 V The increasing order of their reducing capacities is (A)  P < R < S < Q  (B)  Q < S < P < R  (C)  Q < S < R < P  (D)  P < R < Q < S

Tardigrade Admin · Accepted Answer

More negative the reduction potential of a metal, higher is its reducing capacity. Therefore, the increasing order of reduction capacities is

Q + 0.34 V < S - 0.25 V < P - 0.44 V < R - 0.76 V

Q. The standard (reduction) electrode potentials for metal-metal ion $(M / M^{2 +})$ electrodes $P, Q, R$ and $S$ are respectively $- 0.44 V, + 0.34 V, - 0.76 V$ and $- 0.25 V$ The increasing order of their reducing capacities is

$P < R < S < Q$

$Q < S < P < R$

$Q < S < R < P$

$P < R < Q < S$

More negative the reduction potential of a metal, higher is its reducing capacity. Therefore, the increasing order of reduction capacities is
$Q + 0.34 V < S - 0.25 V < P - 0.44 V < R - 0.76 V$

Q. The standard (reduction) electrode potentials for metal-metal ion (M/M2+) electrodes P,Q,R and S are respectively −0.44V,+0.34V,−0.76V and −0.25V The increasing order of their reducing capacities is

P<R<S<Q

Q<S<P<R

Q<S<R<P

P<R<Q<S