Question

The standard oxidation potential $E^0$ for half reactions are
$Zn\to Z{n}^{2+}+2e^{-1};E^0=+0.76V$
$Fe\to F{e}^{2+}+2e^{-1};E^0=+0.41V$
The emf of the cell comprising of above half cells is

• A. -0.35 V
• B. +0.35 V
• C. 1.17 V
• D. - 1.17 V

Answer 1

Answer: (B)

$E_{\text{ecll }}^0=E_{red}^0-E_{\text{oxd }}^0$
$=-0.41-(-0.76)=0.35V$