Question

The standard oxidation potential $E^{0}$ for half reactions are
$Zn \rightarrow Zn ^{2+}+2 e ^{-1} ; E ^{0}=+0.76\, V$
$Fe \rightarrow Fe ^{2+}+2 e ^{-1} ; E ^{0}=+0.41\, V$
The emf of the cell comprising of above half cells is

• A. -0.35 V
• B. +0.35 V
• C. 1.17 V
• D. - 1.17 V

Answer 1

Answer: (B)

$E _{\text {ecll }}^{0}= E _{ red }^{0}- E _{\text {oxd }}^{0}$
$=-0.41-(-0.76)=0.35\, V$