The standard of length is maintained by a 1 meter long bar made up of a material having coefficient of linear expansion α = 0.00001 °C-1. If the length of the bar were to be preserved to an accuracy of 1 part per million, what would be maximum allowed temperature variation?

Question

The standard of length is maintained by a 1 meter long bar made up of a material having coefficient of linear expansion α = 0.00001 °C-1. If the length of the bar were to be preserved to an accuracy of 1 part per million, what would be maximum allowed temperature variation? (A) ± 0.01 °C (B) ± 0.1 °C (C) ± 0.001 °C (D) ± 0.0001 °C

Tardigrade Admin · Accepted Answer

Given, length of bar =1 m and coefficient of linear expansion α=0.00001° C -1 So, expansion of 1 m length Δ L=1 α=1 × 0.00001° C -1 Δ L=10-5 ° C -1 Since, the accurace =1 ppm =± 10-6 Hence, the maximum allowed temperature variation ± Δ T=(10-6/10-5 ° C -1)=± 0.1° C

Q. The standard of length is maintained by a 1 meter long bar made up of a material having coefficient of linear expansion $α = 0.00001^{\circ} C^{- 1}$ . If the length of the bar were to be preserved to an accuracy of 1 part per million, what would be maximum allowed temperature variation?

$\pm 0.01^{\circ} C$

$\pm 0.1^{\circ} C$

$\pm 0.001^{\circ} C$

$\pm 0.0001^{\circ} C$

$\pm 1.0^{\circ} C$

Q. The standard of length is maintained by a 1 meter long bar made up of a material having coefficient of linear expansion α=0.00001∘C−1. If the length of the bar were to be preserved to an accuracy of 1 part per million, what would be maximum allowed temperature variation?

±0.01∘C

±0.1∘C

±0.001∘C

±0.0001∘C

±1.0∘C