The standard enthalpies of formation of A A( NH 3), B( CO 2), C(H I) are respectively -46.19,-393.4,+24,94 and -296.9 kJ mol -1, The increasing order of their stability is

Question

The standard enthalpies of formation of A A( NH 3), B( CO 2), C(H I) are respectively -46.19,-393.4,+24,94 and -296.9 kJ mol -1, The increasing order of their stability is (A) B < D < A < C (B) C < A < D < B (C) D < B < C < A (D) A < C < D < B

Tardigrade Admin · Accepted Answer

Lower the value of standard enthalpy of formation, higher the stability. The increasing order of standard enthalpies of formation of given molecules is

B (C O_{2}) - 393.4 < D (S O_{2}) 296.9 < A (N H_{3}) - 46.19 < C (H I) 24.94

Thus, the increasing order of stability is

C < A < D < B

Q. The standard enthalpies of formation of $A$ $A (N H_{3}), B (C O_{2}), C (H I)$ are respectively $- 46.19, - 393.4, + 24, 94$ and $- 296.9 k J m o l^{- 1}$ , The increasing order of their stability is

$B < D < A < C$

$C < A < D < B$

$D < B < C < A$

$A < C < D < B$

Lower the value of standard enthalpy of formation, higher the stability. The increasing order of standard enthalpies of formation of given molecules is
$B (C O_{2}) - 393.4 < D (S O_{2}) 296.9 < A (N H_{3}) - 46.19 < C (H I) 24.94$
Thus, the increasing order of stability is $C < A < D < B$

Q. The standard enthalpies of formation of A A(NH3​),B(CO2​),C(HI) are respectively −46.19,−393.4,+24,94 and −296.9kJmol−1, The increasing order of their stability is

B<D<A<C

C<A<D<B

D<B<C<A

A<C<D<B