The standard electrode potential (E-)values of -1.66 V , 0.80 V , 2.93 V and -0.74 V, respectively. The correct decreasing order of reducing power of the metal is

Question

The standard electrode potential (E-)values of -1.66 V , 0.80 V , 2.93 V and -0.74 V, respectively. The correct decreasing order of reducing power of the metal is (A) Ag > Cr > Al > K (B) K > Al > Cr > Ag (C) K > Al > Ag > Cr (D) Al > K > Ag > Cr

Tardigrade Admin · Accepted Answer

More negative is the value of standard reduction potential, higher is the reduction power. i.e. Reducing power propto (1/ text standard reduction potential ) Thus, the correct decreasing order of reducing power of the metal is: <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/chemistry/505c680ef3995b781d06467f88ec7e92-.png" />

Q. The standard electrode potential $(E^{-})$ values of $- 1.66 V, 0.80 V, 2.93 V$ and $- 0.74 V$ , respectively. The correct decreasing order of reducing power of the metal is

$A g > C r > A l > K$

$K > A l > C r > A g$

$K > A l > A g > C r$

$A l > K > A g > C r$

More negative is the value of standard reduction potential, higher is the reduction power.
i.e. Reducing power $\propto \frac{1}{standard reduction potential}$
Thus, the correct decreasing order of reducing power of the metal is:

Q. The standard electrode potential (E−)values of −1.66V,0.80V,2.93V and −0.74V, respectively. The correct decreasing order of reducing power of the metal is

Ag>Cr>Al>K

K>Al>Cr>Ag

K>Al>Ag>Cr

Al>K>Ag>Cr