Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Mathematics
The standard deviation of some temperature data in °C is 5. If the data were converted into °F, the new variance would be
Q. The standard deviation of some temperature data in
∘
C
is 5. If the data were converted into
∘
F
, the new variance would be _______
1556
181
Statistics
Report Error
Answer:
81
Solution:
Given,
σ
C
=
5
Relation between
∘
C
and
∘
F
is given by
F
=
5
9
C
+
32
∴
σ
F
=
5
9
σ
C
=
5
9
×
5
=
9
Here,
σ
F
2
=
(
9
)
2
=
81