The standard variance of 35, 40, 42, 36, 27 :

Question

The standard variance of 35, 40, 42, 36, 27 : (A) 25.8 (B) 26.9 (C) 26.8 (D) 27.8

Tardigrade Admin · Accepted Answer

Given: x i =35,40,42,36,27 and n =5 <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/mathematics/e28f085a655ee8e7b4f3317c9ff00f68-.png" /> ∑ x i =180 ∑ x i 2=6614 ∴ variance =(∑ xi 2/ n )-((∑ xi / n ))2 =(6614/5)-((180/5))2=1322.8-1296=26.8

Q. The standard variance of 35, 40, 42, 36, 27 :

25.8

26.9

26.8

27.8

Given : $x_{i} = 35, 40, 42, 36, 27$ and $n = 5$

$\sum x_{i} = 180 \sum x_{i}^{2} = 6614$
$∴$ variance $= \frac{\sum x i ^{2}}{n} - (\frac{\sum x i}{n})^{2}$
$= \frac{6614}{5} - (\frac{180}{5})^{2} = 1322.8 - 1296 = 26.8$

Q. The standard variance of 35, 40, 42, 36, 27 :

25.8

26.9

26.8

27.8

Given : xi​=35,40,42,36,27 and n=5 ∑xi​=180∑xi2​=6614 ∴ variance =n∑xi2​−(n∑xi​)2 =56614​−(5180​)2=1322.8−1296=26.8

Given : $x_{i} = 35, 40, 42, 36, 27$ and $n = 5$

$\sum x_{i} = 180 \sum x_{i}^{2} = 6614$
$∴$ variance $= \frac{\sum x i ^{2}}{n} - (\frac{\sum x i}{n})^{2}$
$= \frac{6614}{5} - (\frac{180}{5})^{2} = 1322.8 - 1296 = 26.8$