The spin only magnetic moment value (in Bohr's magneton units) of [.Cr(. CO .)6]. is:

Question

The spin only magnetic moment value (in Bohr's magneton units) of [.Cr(. CO .)6]. is: (A) 0 (B) 2.84 (C) 4.90 (D) 5.92

Tardigrade Admin · Accepted Answer

In [ textC textr (. textC textO .)6] , textC textr has 3 textd6 electronic configuration which has no unpaired electrons and hence, zero magnetic moment. CO is a strong field ligand which causes pairing up of unpaired electrons in d-orbitals of central metal atom.

Q. The spin only magnetic moment value (in Bohr's magneton units) of $[C r (CO)_{6}]$ is:

0

2.84

4.90

5.92

In $[C r (C O)_{6}], C r$ has $3 d^{6}$ electronic configuration which has no unpaired electrons and hence, zero magnetic moment.
CO is a strong field ligand which causes pairing up of unpaired electrons in d-orbitals of central metal atom.

Q. The spin only magnetic moment value (in Bohr's magneton units) of [Cr(CO)6​] is:

0

2.84

4.90

5.92

In [Cr(CO)6​],Cr has 3d6 electronic configuration which has no unpaired electrons and hence, zero magnetic moment. CO is a strong field ligand which causes pairing up of unpaired electrons in d-orbitals of central metal atom.

Q. The spin only magnetic moment value (in Bohr's magneton units) of $[C r (CO)_{6}]$ is:

In $[C r (C O)_{6}], C r$ has $3 d^{6}$ electronic configuration which has no unpaired electrons and hence, zero magnetic moment.
CO is a strong field ligand which causes pairing up of unpaired electrons in d-orbitals of central metal atom.