The spin only magnetic moment value (in B.M. unit) of Cr(CO)6 is

Question

The spin only magnetic moment value (in B.M. unit) of Cr(CO)6 is (A) 0 (B) 2.84 (C) 4.90 (D) 5.92

Tardigrade Admin · Accepted Answer

In Cr(CO)6, Cr is present as Cr0 Cr or Cr0=[Ar] 3d5 4S1 CO being strong field ligand pair up the unpaired electrons of Cr <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/chemistry/7849e81da30252dd0cacb1d1e0ab5946-.jpeg" /> In this condition, number of unpaired electrons, n=0 Magnetic moment, μ= √n(n+2) =√0(0+2) =0 BM

Q. The spin only magnetic moment value (in B.M. unit) of $C r (CO)_{6}$ is

0

2.84

4.90

5.92

In $C r (CO)_{6}$ , $C r$ is present as $C r^{0}$
$C r$ or $C r^{0} = [A r] 3 d^{5} 4 S^{1}$
$CO$ being strong field ligand pair up the unpaired electrons of $C r$

In this condition,
number of unpaired electrons, $n = 0$
Magnetic moment, $μ = n (n + 2)$
$= 0 (0 + 2)$
$= 0 BM$

Q. The spin only magnetic moment value (in B.M. unit) of Cr(CO)6​ is

0

2.84

4.90

5.92

In Cr(CO)6​, Cr is present as Cr0 Cr or Cr0=[Ar]3d54S1 CO being strong field ligand pair up the unpaired electrons of Cr In this condition, number of unpaired electrons, n=0 Magnetic moment, μ=n(n+2)​ =0(0+2)​ =0BM

Q. The spin only magnetic moment value (in B.M. unit) of $C r (CO)_{6}$ is

In $C r (CO)_{6}$ , $C r$ is present as $C r^{0}$
$C r$ or $C r^{0} = [A r] 3 d^{5} 4 S^{1}$
$CO$ being strong field ligand pair up the unpaired electrons of $C r$

In this condition,
number of unpaired electrons, $n = 0$
Magnetic moment, $μ = n (n + 2)$
$= 0 (0 + 2)$
$= 0 BM$