Question

The "spin only" magnetic moment of $N{i}^{2+}$ in aqueous solution would be [At No. of $Ni=28$]

• A. $\sqrt{6}BM$
• B. $\sqrt{1}5BM$
• C. $\sqrt{2}BM$
• D. $\sqrt{8}BM$

Answer 1

Answer: (D)

$N{i}^{2+}$ in aqueous solution refers to ${\left[Ni{\left(H_{2}O\right)}_6\right]}^{2+}.N{i}^{2+}$ has following electronic orientation.



$\therefore$ Number of unpaired electrons $=2$

Spin only magnetic moment $=\sqrt{n(n+2)}$

$=\sqrt{2(2+2)}=\sqrt{8}BM$