The spin magnetic moment of cobalt in the compound Hg[Co(SCN)4] is

Question

The spin magnetic moment of cobalt in the compound Hg[Co(SCN)4] is (A) √3 (B) √8 (C) √15 (D) √24

Tardigrade Admin · Accepted Answer

In Hg[Co(SCN)4], the oxidation state of Co is +2. In Co2+; 1s2 2s2 2p6 3s2 3p6 3d7, we have three unpaired electrons so its spin magnetic moment will be μ = √3(3 + 2) B.M. = √ 3 × 5 B.M. = √15B.M.

Q. The spin magnetic moment of cobalt in the compound $H g [C o (SCN)_{4}]$ is

$3$

$8$

$15$

$24$

In $H g [C o (SCN)_{4}]$ , the oxidation state of $C o$ is $+ 2$ .
In $C o^{2 +}; 1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{6} 3 d^{7}$ , we have three unpaired electrons so its spin magnetic moment will be
$μ = 3 (3 + 2) B . M . = 3 \times 5 B . M .$
$= 15 B . M$ .

Q. The spin magnetic moment of cobalt in the compound Hg[Co(SCN)4​] is

3​

8​

15​

24​

In Hg[Co(SCN)4​], the oxidation state of Co is +2. In Co2+;1s22s22p63s23p63d7, we have three unpaired electrons so its spin magnetic moment will be μ=3(3+2)​B.M.=3×5​B.M. =15​B.M.

Q. The spin magnetic moment of cobalt in the compound $H g [C o (SCN)_{4}]$ is

$3$

$8$

$15$

$24$

In $H g [C o (SCN)_{4}]$ , the oxidation state of $C o$ is $+ 2$ .
In $C o^{2 +}; 1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{6} 3 d^{7}$ , we have three unpaired electrons so its spin magnetic moment will be
$μ = 3 (3 + 2) B . M . = 3 \times 5 B . M .$
$= 15 B . M$ .