The speed-time graph for a body moving along a straight line is shown in figure. The average acceleration of body may be

Question

The speed-time graph for a body moving along a straight line is shown in figure. The average acceleration of body may be (A) 0 (B) 4 m / s 2 (C) -4 m / s 2 (D) All of these

Tardigrade Admin · Accepted Answer

The acceleration from zero to 5 s is a=(0-20/5-0)=(-20/5)=-4 ms -2 From 5 s to 10 s a=(20-0/10-5)=4 ms -2 a=( text Total change in velocity / text Time ) =(20-20/10-0)=0 ms -2

Q. The speed-time graph for a body moving along a straight line is shown in figure. The average acceleration of body may be

$0$

$4 m / s^{2}$

$- 4 m / s^{2}$

All of these

The acceleration from zero to $5 s$ is
$a = \frac{0 - 20}{5 - 0} = \frac{- 20}{5} = - 4 m s^{- 2}$
From $5 s$ to $10 s$
$a = \frac{20 - 0}{10 - 5} = 4 m s^{- 2}$
$a = \frac{Total change in velocity}{Time}$
$= \frac{20 - 20}{10 - 0} = 0 m s^{- 2}$

Q. The speed-time graph for a body moving along a straight line is shown in figure. The average acceleration of body may be

0

4m/s2

−4m/s2

All of these

The acceleration from zero to 5s is a=5−00−20​=5−20​=−4ms−2 From 5s to 10s a=10−520−0​=4ms−2 a= Time Total change in velocity ​ =10−020−20​=0ms−2

$0$

$4 m / s^{2}$

$- 4 m / s^{2}$

The acceleration from zero to $5 s$ is
$a = \frac{0 - 20}{5 - 0} = \frac{- 20}{5} = - 4 m s^{- 2}$
From $5 s$ to $10 s$
$a = \frac{20 - 0}{10 - 5} = 4 m s^{- 2}$
$a = \frac{Total change in velocity}{Time}$
$= \frac{20 - 20}{10 - 0} = 0 m s^{- 2}$