Question

The speed of a projectile at its maximum height is half of its initial speed. The angle of projection is

• A. $60^{\circ }$
• B. $15^{\circ }$
• C. $30^{\circ }$
• D. $45^{\circ }$

Answer 1

Answer: (A)

Let $v$ be velocity of a projectile at maximum height $H$.

$v=\cos \theta$
According to given problem, v = $\frac{u}{2}$
$\therefore \frac{u}{2}=u\cos \theta$
$\Rightarrow \cos \theta =\frac{1}{2}$
$\Rightarrow \theta =60^{\circ }$