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Q. The speed of a projectile at its maximum height is half of its initial speed. The angle of projection is

AIPMTAIPMT 2010Motion in a Plane

Solution:

Let $v$ be velocity of a projectile at maximum height $H$.
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$v = \cos \theta$
According to given problem, v = $ \frac{ u}{ 2} $
$\therefore \frac{u}{2} = u \, \cos \, \theta$
$ \Rightarrow \cos \, \theta = \frac{1}{2}$
$\Rightarrow \theta = 60^\circ$