Thank you for reporting, we will resolve it shortly
Q.
The speed of a projectile at its maximum height is half of its initial speed. The angle of projection is
AIPMTAIPMT 2010Motion in a Plane
Solution:
Let $v$ be velocity of a projectile at maximum height $H$.
$v = \cos \theta$
According to given problem, v = $ \frac{ u}{ 2} $
$\therefore \frac{u}{2} = u \, \cos \, \theta$
$ \Rightarrow \cos \, \theta = \frac{1}{2}$
$\Rightarrow \theta = 60^\circ$