The specific heats of an ideal gas at constant pressure and constant volume are 525 J kg° C- 1 and 315 J kg° C- 1 respectively. Its density at NTP is

Question

The specific heats of an ideal gas at constant pressure and constant volume are 525 J kg° C- 1 and 315 J kg° C- 1 respectively. Its density at NTP is (A) 0.64 kg m- 3 (B) 1.20 kg m- 3 (C) 1.75 kg m- 3 (D) 2.62 kg m- 3

Tardigrade Admin · Accepted Answer

If M is molecular mass of the gas, then from M(Cp - Cv)=R M=(8.31/210)=0.0392 If ρ is density of the gas at NTP, then mass of 1 m3 of gas at NTP =ρ kg ∴ Mass of 22.4 L (=22.4 × 10-3 m 3) of gas at NTP =ρ × 22.4 × 10-3 kg, which is the molecular mass of the gas ∴ ρ × 22.4× 10- 3=0.0392 ρ =(0.0392/22.4 × 10- 3)=1.75 kg m- 3

Q. The specific heats of an ideal gas at constant pressure and constant volume are $525 J$ $k g^{\circ} C^{- 1}$ and $315 J k g^{\circ} C^{- 1}$ respectively. Its density at NTP is

$0.64 k g m^{- 3}$

$1.20 k g m^{- 3}$

$1.75 k g m^{- 3}$

$2.62 k g m^{- 3}$

Q. The specific heats of an ideal gas at constant pressure and constant volume are 525J kg∘C−1 and 315Jkg∘C−1 respectively. Its density at NTP is

0.64kgm−3

1.20kgm−3

1.75kgm−3

2.62kgm−3

Q. The specific heats of an ideal gas at constant pressure and constant volume are $525 J$ $k g^{\circ} C^{- 1}$ and $315 J k g^{\circ} C^{- 1}$ respectively. Its density at NTP is

$0.64 k g m^{- 3}$

$1.20 k g m^{- 3}$

$1.75 k g m^{- 3}$

$2.62 k g m^{- 3}$