Q.
The specific heat of air at constant volume is 0.172Calg−1∘C−1. The change in internal energy when 5g of air is heated from 0∘C to 4∘C at constant volume is
Given: Specific heat of air =0172Cal/gC
Mass of air =5g
Initial temperature =0C
Final temperature =4C
Solution: At constant volume the change in internal energy is given by, ΔU=mCp△T
As, △T=4−0=4C
Substituting the values we get, ΔU=3.44Cal
Also, 1Cal=4.2J ∴△U=4.2J×3.44=14.188J∼14.4J