The specific conductance of AgCl solution in water was determined to be 1.8× 10- 6Ω- 1cm- 1at298K . The molar conductances at infinite dilution of Ag+ & Cl- are 67.9 &82.1Ω- 11cm2mol- 1 . What is the solubility of AgCl in water ?

Question

The specific conductance of AgCl solution in water was determined to be 1.8× 10- 6Ω- 1cm- 1at298K . The molar conductances at infinite dilution of Ag+ & Cl- are 67.9 &82.1Ω- 11cm2mol- 1 . What is the solubility of AgCl in water ? (A) 1.2× 10- 8M (B) 1.44× 10- 10M (C) 1.2× 10- 5M (D) 1.44× 10- 16M

Tardigrade Admin · Accepted Answer

LambdaM (. AgCl .)∞ = LambdaM ((Ag)+)∞ + LambdaM ((Cl)-)∞ =67.9+82.1 =150cm2mol- 1ohm- 1 LambdaM∞ =(K × 1000/ S) 150=(1 . 8 × 10- 6 × 103/ S) S=1.2× 10- 5M

Q. The specific conductance of $A g Cl$ solution in water was determined to be $1.8 \times 1 0^{- 6} Ω^{- 1} c m^{- 1} a t 298 K$ . The molar conductances at infinite dilution of $A g^{+}$ & $C l^{-}$ are $67.9&82.1 Ω^{- 1} 1 c m^{2} m o l^{- 1}$ . What is the solubility of $A g Cl$ in water ?

$1.2 \times 1 0^{- 8} M$

$1.44 \times 1 0^{- 10} M$

$1.2 \times 1 0^{- 5} M$

$1.44 \times 1 0^{- 16} M$

$Λ_{M (A g Cl)}^{\infty} = Λ_{M ((A g)^{+})}^{\infty} + Λ_{M ((Cl)^{-})}^{\infty}$
$= 67.9 + 82.1$
$= 150 c m^{2} m o l^{- 1} o h m^{- 1}$
$Λ_{M}^{\infty} = \frac{K \times 1000}{S}$
$150 = \frac{1.8 \times 1 0 ^{- 6} \times 1 0 ^{3}}{S}$
$S = 1.2 \times 1 0^{- 5} M$

Q. The specific conductance of AgCl solution in water was determined to be 1.8×10−6Ω−1cm−1at298K . The molar conductances at infinite dilution of Ag+ & Cl− are 67.9&82.1Ω−11cm2mol−1 . What is the solubility of AgCl in water ?

1.2×10−8M

1.44×10−10M

1.2×10−5M

1.44×10−16M