Tardigrade
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Tardigrade
Question
Chemistry
The sp3d2 hybridization of central atom of a molecule would lead to
Q. The
s
p
3
d
2
hybridization of central atom of a molecule would lead to
3254
207
WBJEE
WBJEE 2011
Chemical Bonding and Molecular Structure
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A
square planar geometry
11%
B
tetrahedral geometry
6%
C
trigonal bipyramidal geometry
31%
D
octahedral geometry
53%
Solution:
The
s
p
3
d
2
and
d
2
s
p
3
hybridization of central atom leads to octahedral geometry.