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Question
Mathematics
The solutions of the equation | x&2 &-1 2&5& x -1&z&x | =0 are
Q. The solutions of the equation
∣
∣
x
2
−
1
2
5
z
−
1
x
x
∣
∣
=
0
are
2335
198
KCET
KCET 2005
Determinants
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A
3,-1
22%
B
-3,1
33%
C
3,1
29%
D
-3,-1
16%
Solution:
Since,
∣
∣
x
2
−
1
2
5
2
−
1
x
x
∣
∣
=
0
⇒
∣
∣
x
2
−
3
2
5
−
3
−
1
x
0
∣
∣
=
0
R
3
→
R
3
−
R
2
⇒
−
1
(
−
6
+
15
)
−
x
[
−
3
x
+
6
]
=
0
⇒
−
9
+
3
x
2
−
6
x
=
0
⇒
x
2
−
2
x
−
3
=
0
⇒
(
x
−
3
)
(
x
+
1
)
=
0
x
=
−
1
,
3