Question

The solution set of the inequality $3(x-1)\le 2(x-3)$ is ...A .... Here, A refers to

• A. $(-\infty ,3)$
• B. $(-\infty ,-3)$
• C. $(-\infty ,3]$
• D. $(-\infty ,-3]$

Answer 1

Answer: (D)

We have, $3x-3\le 2x-6$
Transferring the term $2x$ to LHS and the term - 3 to $RHS$,
$3x-2x\le -6+3$
$\Rightarrow x\le -3$