We have 3x−7>2(x−6) ⇒3x−7>2x−12
Transferring the term 2x to L.H.S. and the term (−7) to R.H.S.,3x−2x>−12+7 ⇒x>−5...(i)
and 6−x>11−2x
Transferring the term (−2x) to L.H.S. and the term 6 to R.H.S.,−x+2x>11−6 ⇒x>5...(ii)
Draw the graph of inequations (i) and (ii) on the number line,
Hence, solution set of the equations are real numbers, x lying on greater than 5 excluding 5. i.e., x>5∴ Solution set is (5,∞)