The solution of the differential equation (y dx + x dy/y dx - x dy) = (x2 exy/y4) satisfying y(0) = 1, is :

Question

The solution of the differential equation (y dx + x dy/y dx - x dy) = (x2 exy/y4) satisfying y(0) = 1, is : (A) x3 = 3y3 (1 - e-xy ) (B) x3 = 3y3 ( - 1 + exy ) (C) x3 = 3y3 (1 - exy ) (D) x3 = 3y3 (- 1 + e-xy )

Tardigrade Admin · Accepted Answer

Correct answer is (a) x3 = 3y3 (1 - e-xy )

Q. The solution of the differential equation $\frac{y d x + x d y}{y d x - x d y} = \frac{x ^{2} e ^{x y}}{y ^{4}}$ satisfying $y (0) = 1$ , is :

$x^{3} = 3 y^{3} (1 - e^{- x y})$

$x^{3} = 3 y^{3} (- 1 + e^{x y})$

$x^{3} = 3 y^{3} (1 - e^{x y})$

$x^{3} = 3 y^{3} (- 1 + e^{- x y})$

Correct answer is (a) $x^{3} = 3 y^{3} (1 - e^{- x y})$

Q. The solution of the differential equation ydx−xdyydx+xdy​=y4x2exy​ satisfying y(0)=1, is :

x3=3y3(1−e−xy)

x3=3y3(−1+exy)

x3=3y3(1−exy)

x3=3y3(−1+e−xy)