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Question
Mathematics
The solution of the differential equation 3sin2 xcosxy2dx+2ysin3xdy=sinxdx is (where, C is an arbitrary constant)
Q. The solution of the differential equation
3
s
i
n
2
x
cos
x
y
2
d
x
+
2
ys
i
n
3
x
d
y
=
s
in
x
d
x
is (where,
C
is an arbitrary constant)
1479
221
NTA Abhyas
NTA Abhyas 2020
Differential Equations
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A
2
y
2
s
in
x
=
cos
x
+
C
B
y
2
s
i
n
3
x
+
cos
x
=
C
C
y
3
s
i
n
2
x
+
s
in
x
=
C
D
ys
in
x
=
co
s
2
x
+
C
Solution:
The given equation is
d
(
y
2
(
s
in
)
3
x
)
=
s
in
x
d
x
On integrating, we get,
∫
d
(
y
2
(
s
in
)
3
x
)
=
∫
s
in
x
d
x
⇒
y
2
s
i
n
3
x
=
−
cos
x
+
C
or
y
2
s
i
n
3
x
+
cos
x
=
C