The solution for minimizing the function z = x + y under a L.P.P. with constraints x + y ≥ 1 , x+ 2y ≤ 10 , y ≤ 4 and x, y ≥ 0 , is

Question

The solution for minimizing the function z = x + y under a L.P.P. with constraints x + y ≥ 1 , x+ 2y ≤ 10 , y ≤ 4 and x, y ≥ 0 , is (A) x = 0 , y = 0 , z = 0 (B) x = 3, y = 3 , z = 6 (C) There are infinitely solutions (D) None of these

Tardigrade Admin · Accepted Answer

Objective function is same as constraints so there are infinite solutions possible.

Q. The solution for minimizing the function $z = x + y$ under a L.P.P. with constraints $x + y \geq 1, x + 2 y \leq 10, y \leq 4$ and $x, y \geq 0,$ is

$x = 0, y = 0, z = 0$

$x = 3, y = 3, z = 6$

There are infinitely solutions

None of these

Objective function is same as constraints so there are infinite solutions possible.

Q. The solution for minimizing the function z=x+y under a L.P.P. with constraints x+y≥1,x+2y≤10,y≤4 and x,y≥0, is

x=0,y=0,z=0

x=3,y=3,z=6

There are infinitely solutions

None of these

Objective function is same as constraints so there are infinite solutions possible.

Q. The solution for minimizing the function $z = x + y$ under a L.P.P. with constraints $x + y \geq 1, x + 2 y \leq 10, y \leq 4$ and $x, y \geq 0,$ is

$x = 0, y = 0, z = 0$

$x = 3, y = 3, z = 6$