Question

The solubility product values of barium sulphate and barium carbonate are $1.0\times 10^{-10}\text{and}5.0\times 10^{-9}$ respectively When the two salts are simultaneously equilibrated in pure water the ratio of $\frac{\left[S{O}_4^{2-}\right]}{\left[C{O}_3^{2-}\right]}$ is

• A. 0.02
• B. 0.10
• C. 0.05
• D. 0.12

Answer 1

Answer: (A)

${\text{K}}_{{\text{sp}}_1}=\left[{\text{Ba}}^{2+}\right]\left[{\text{SO}}_4^{2-}\right]$
${\text{K}}_{{\text{sp}}_2}=\left[{\text{Ba}}^{2+}\right]\left[{\text{CO}}_3^{2-}\right]$
$\frac{{\text{K}}_{{\text{sp}}_1}}{{\text{K}}_{{\text{sp}}_2}}=\frac{{\text{SO}}_4^{2-}}{{\text{CO}}_3^{2-}}=\frac{1\times 10^{-10}}{5\times 10^{-9}}=\text{0.02}$