Question

The solubility product values of barium sulphate and barium carbonate are $1.0\times 10^{- 10}\text{and}5.0\times 10^{- 9}$ respectively When the two salts are simultaneously equilibrated in pure water the ratio of $\frac{\left[SO_{4}^{2 -}\right]}{\left[CO_{3}^{2 -}\right]}$ is

• A. 0.02
• B. 0.10
• C. 0.05
• D. 0.12

Answer 1

Answer: (A)

$\text{K}_{\text{sp}_{1}} = \left[\text{Ba}^{2 +}\right] \left[\text{SO}_{4}^{2 -}\right]$
$\text{K}_{\text{sp}_{2}} = \left[\text{Ba}^{2 +}\right] \left[\text{CO}_{3}^{2 -}\right]$
$\frac{\text{K}_{\text{sp}_{1}}}{\text{K}_{\text{sp}_{2}}} = \frac{\text{SO}_{4}^{2 -}}{\text{CO}_{3}^{2 -}} = \frac{1 \times 1 0^{- 1 0}}{5 \times 1 0^{- 9}} = \text{0.02}$