The solubility product of Ni ( OH )2 is 2.0 × 10-15 . The molar solubility of Ni ( OH )2 in 0.10 M NaOH is

Question

The solubility product of Ni ( OH )2 is 2.0 × 10-15 . The molar solubility of Ni ( OH )2 in 0.10 M NaOH is (A) 3.2 × 10-12 (B) 2.0 × 10-13 (C) 4.34 × 10-12 (D) 0.58 × 10-4

Tardigrade Admin · Accepted Answer

Ni ( OH )2 leftharpoons undersetsNi2++ underset2s2OH- Total [ OH -]=2 s+0.1 Solubility product =(s)(2s+0.1)2 =4 s3+0.4 s2+0.01 s=2 × 10-15 s is very small so by neglecting 4 s3 and 0.4 s2 0.01 s=2 × 10-15 ⇒ s=2 × 10-13

Q. The solubility product of $N i (O H)_{2}$ is $2.0 \times 1 0^{- 15} .$ The molar solubility of $N i (O H)_{2}$ in $0.10 M N a O H$ is

$3.2 \times 1 0^{- 12}$

$2.0 \times 1 0^{- 13}$

$4.34 \times 1 0^{- 12}$

$0.58 \times 1 0^{- 4}$

Q. The solubility product of Ni(OH)2​ is 2.0×10−15. The molar solubility of Ni(OH)2​ in 0.10MNaOH is

3.2×10−12

2.0×10−13

4.34×10−12

0.58×10−4

Ni(OH)2​⇌sNi2+​+2s2OH−​ Total [OH−]=2s+0.1 Solubility product =(s)(2s+0.1)2 =4s3+0.4s2+0.01s=2×10−15 s is very small so by neglecting 4s3 and 0.4s2 0.01s=2×10−15 ⇒s=2×10−13

Q. The solubility product of $N i (O H)_{2}$ is $2.0 \times 1 0^{- 15} .$ The molar solubility of $N i (O H)_{2}$ in $0.10 M N a O H$ is

$3.2 \times 1 0^{- 12}$

$2.0 \times 1 0^{- 13}$

$4.34 \times 1 0^{- 12}$

$0.58 \times 1 0^{- 4}$