The solubility product of AgI at 25° C is 1.0 × 10-16 mol 2 L -2. The solubility of AgI in 10-4 N solution of KI at 25° C is approximately (in mol L -1 )

Question

The solubility product of AgI at 25° C is 1.0 × 10-16 mol 2 L -2. The solubility of AgI in 10-4 N solution of KI at 25° C is approximately (in mol L -1 ) (A)  1.0 × 10-10  (B)  1.0 × 10-8  (C)  1.0 × 10-16  (D)  1.0 × 10-12

Tardigrade Admin · Accepted Answer

A g I arrow A g++I- For binary electrolyte Ks p=S2 where, S= solubility in mol / L 1.0 × 10-16=S2 or S=1 × 10-8 mol / L Solubility of Agl in KI solution =1 × 10-8 × 10-4 =1 × 10-12 mol / L

Q. The solubility product of $A g I$ at $2 5^{\circ} C$ is $1.0 \times 1 0^{- 16} m o l^{2} L^{- 2}$ . The solubility of $A g I$ in $1 0^{- 4} N$ solution of $K I$ at $2 5^{\circ} C$ is approximately (in mol L $^{- 1}$ )

$1.0 \times 1 0^{- 10}$

$1.0 \times 1 0^{- 8}$

$1.0 \times 1 0^{- 16}$

$1.0 \times 1 0^{- 12}$

$A g I \to A g^{+} + I^{-}$
For binary electrolyte
$K_{s p} = S^{2}$
where, $S =$ solubility in mol $/ L$
$1.0 \times 1 0^{- 16} = S^{2}$
or $S = 1 \times 1 0^{- 8} m o l / L$
Solubility of $A g l$ in $K I$ solution
$= 1 \times 1 0^{- 8} \times 1 0^{- 4}$
$= 1 \times 1 0^{- 12} m o l / L$

Q. The solubility product of AgI at 25∘C is 1.0×10−16mol2L−2. The solubility of AgI in 10−4N solution of KI at 25∘C is approximately (in mol L −1 )

1.0×10−10

1.0×10−8

1.0×10−16

1.0×10−12