The solubility product of AgCl is 1.5625 × 10-10 at 25 °C. Its solubility in grams per litre will be

Question

The solubility product of AgCl is 1.5625 × 10-10 at 25 °C. Its solubility in grams per litre will be (A) 143.5 (B) 108 (C) 1.57×10-8 (D) 1.79×10-3

Tardigrade Admin · Accepted Answer

AgCl leftharpoons underset textsAg++ underset textsCl- s2=1.5625×10-10 s=1.25×10-5 mol L-1 Solubility in g L-1= Molar mass × s =143.5×1.25×10-5 =1.79×10-3 g L-1

Q. The solubility product of $A g Cl$ is $1.5625 \times 1 0^{- 10}$ at $25^{\circ} C$ . Its solubility in grams per litre will be

$143.5$

$108$

$1.57 \times 1 0^{- 8}$

$1.79 \times 1 0^{- 3}$

$A g Cl ⇌ s A g^{+} + s C l^{-}$
$s^{2} = 1.5625 \times 1 0^{- 10}$
$s = 1.25 \times 1 0^{- 5} m o l L^{- 1}$
Solubility in $g L^{- 1} =$ Molar mass $\times s$
$= 143.5 \times 1.25 \times 1 0^{- 5}$
$= 1.79 \times 1 0^{- 3} g L^{- 1}$

Q. The solubility product of AgCl is 1.5625×10−10 at 25∘C. Its solubility in grams per litre will be

143.5

108

1.57×10−8

1.79×10−3