1. Tardigrade
  2. Question
  3. Chemistry
  4. The solubility product of AgCl is 1.5625 × 10-10 at 25 °C. Its solubility in grams per litre will be

Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. The solubility product of $AgCl$ is $1.5625 \times 10^{-10}$ at $25 \,{}^{\circ}C$. Its solubility in grams per litre will be

Equilibrium

Solution:

$AgCl \rightleftharpoons \underset{\text{s}}{Ag^+}+ \underset{\text{s}}{Cl^-}$
$s^{2}=1.5625\times10^{-10}$
$s=1.25\times10^{-5}\,mol\,L^{-1}$
Solubility in $g\,L^{-1}=$ Molar mass $\times s$
$=143.5\times1.25\times10^{-5}$
$=1.79\times10^{-3}\,g\,L^{-1}$