The solubility product of a sparingly soluble A B2 salt is 2.56 × 10-4 M3 at 25° C. The Kf of water is 1.8 kg mol -. The depression in freezing point of a standard solution of A B2 is

Question

The solubility product of a sparingly soluble A B2 salt is 2.56 × 10-4 M3 at 25° C. The Kf of water is 1.8 kg mol -. The depression in freezing point of a standard solution of A B2 is (A) 0.432 K (B) 0.216 K (C) 0.108 K (D) 13.824 K

Tardigrade Admin · Accepted Answer

Let, solubility of A B2(1: 2 type electrolyte ) is pure water =5 mol L-1=5 M ⇒ Ks p=4 S3=2.56 × 10-4 M3 (given) ∴ S=0.04 M=0.04 m (molal) under standard condition of the solution. Depression of freezing point, Δ Tf=Kf × m × i=1.8 × 0.04 × 3 =0.216 K [ ∵ Assuming complete dissociation of A B2 van't Hoff factor, i=3]

Q. The solubility product of a sparingly soluble AB2​ salt is 2.56×10−4M3 at 25∘C. The Kf​ of water is 1.8kgmol−. The depression in freezing point of a standard solution of AB2​ is

0.432 K

0.216 K

0.108 K

13.824 K

Q. The solubility product of a sparingly soluble $A B_{2}$ salt is $2.56 \times 1 0^{- 4} M^{3}$ at $2 5^{\circ} C$ . The $K_{f}$ of water is $1.8 k g m o l^{-}$ . The depression in freezing point of a standard solution of $A B_{2}$ is