The solubility of Mg(OH)2 in pure water is 9.57 × 10 - 3 g/L. Calculate its solubility (in g/L) in 0.02 M Mg(N3 )2 solution

Question

The solubility of Mg(OH)2 in pure water is 9.57 × 10 - 3 g/L. Calculate its solubility (in g/L) in 0.02 M Mg(N3 )2 solution (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

In pure water, solubility = ( 9.57/ 58) × 10 - 3 M = 1.65 × 10 - 3 M K sp = 4S3 = 4 ( 1.65 × 10 - 4 )3 = 1.8 × 10 - 11 In 0.02 M Mg(NO3)2 solubility of Mg(OH)2 = √ ( K sp/ [ Mg 2 + ] ) × (1/2) = 1.5 × 10 - 5 mol L - 1 = 1.5 × 10 - 5 × 58 g L - 1 = 8.7 × 10 - 4 g L - 1

Q. The solubility of Mg(OH)2​ in pure water is 9.57×10−3g/L. Calculate its solubility (in g/L) in 0.02MMg(N3​)2​ solution

In pure water, solubility = 589.57​×10−3 M = 1.65×10−3M Ksp​=4S3=4(1.65×10−4)3=1.8×10−11 In 0.02MMg(NO3​)2​ solubility of Mg(OH)2​=[Mg2+]Ksp​​​×21​ =1.5×10−5 mol L−1 =1.5×10−5×58gL−1 =8.7×10−4gL−1

Q. The solubility of $M g (O H)_{2}$ in pure water is $9.57 \times 1 0^{- 3} g / L$ . Calculate its solubility (in $g / L$ ) in $0.02 M M g (N_{3})_{2}$ solution