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Tardigrade
Question
Chemistry
The solubility of Ca3(PO4)2 in water is y moles / litre. Its solubility product is
Q. The solubility of
C
a
3
(
P
O
4
)
2
in water is y moles / litre. Its solubility product is
3095
180
WBJEE
WBJEE 2011
Equilibrium
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A
6
y
4
0%
B
36
y
4
0%
C
64
y
5
0%
D
108
y
5
100%
Solution:
C
a
3
(
P
O
4
)
2
(
s
)
⇌
3y
3
C
a
2
+
(
a
q
)
+
2y
2
P
O
4
3
−
(
a
q
)
∴
K
s
p
=
[
C
a
2
+
]
3
⋅
[
P
O
4
3
−
]
2
=
(
3
y
)
3
⋅
(
2
y
)
2
=
27
y
3
×
4
y
2
=
108
y
5