The solubility of AgCl(s) with solubility product 1.6× 10- 10 in 0.1MNaCl solution would be :

Question

The solubility of AgCl(s) with solubility product 1.6× 10- 10 in 0.1MNaCl solution would be : (A) 1.6× 10- 9M (B) 1.6× 10- 11M (C) Zero (D) 1.26× 10- 5M

Tardigrade Admin · Accepted Answer

S'=(Ksp/C)⇒ S'=(1 . 6 × 10- 10/0 . 1) S'=1.6× 10- 9M

Q. The solubility of $A g Cl (s)$ with solubility product $1.6 \times 1 0^{- 10}$ in $0.1 MN a Cl$ solution would be :

$1.6 \times 1 0^{- 9} M$

$1.6 \times 1 0^{- 11} M$

Zero

$1.26 \times 1 0^{- 5} M$

$S^{^{'}} = \frac{K _{s p}}{C} \Rightarrow S^{^{'}} = \frac{1.6 \times 1 0 ^{- 10}}{0.1}$
$S^{^{'}} = 1.6 \times 1 0^{- 9} M$

Q. The solubility of AgCl(s) with solubility product 1.6×10−10 in 0.1MNaCl solution would be :

1.6×10−9M

1.6×10−11M