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  4. The solubility of AgCl(s) with solubility product 1.6× 10- 10 in 0.1MNaCl solution would be :

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Q. The solubility of $AgCl\left(s\right)$ with solubility product $1.6\times 10^{- 10}$ in $0.1MNaCl$ solution would be :

NTA AbhyasNTA Abhyas 2020

Solution:

$S^{'}=\frac{K_{sp}}{C}\Rightarrow S^{'}=\frac{1 . 6 \times 10^{- 10}}{0 . 1}$
$S^{'}=1.6\times 10^{- 9}M$