The solubility of a sparingly soluble salt A(OH)2 (mol. wt. 192.3) is 19.23 g/litre at 300 K . The pH of its saturated solution assuming 80% ionisation at 300 K is :

Question

The solubility of a sparingly soluble salt A(OH)2 (mol. wt. 192.3) is 19.23 g/litre at 300 K . The pH of its saturated solution assuming 80% ionisation at 300 K is : (A) 1.0970 (B) 12.9030 (C) 13.2041 (D) 12.0000

Tardigrade Admin · Accepted Answer

textS = ( text19.23/ text192.3) textmol/litre = text0.1 M <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/chemistry/1f462669c10009235267e35dc2790136-.png" /> â´ [ textOH-] = ( text0.1 × 2 × 8 0/1 0 0) = text0.16 â´ textpOH = text0.7958 â´ textpH = text13.2041

Q. The solubility of a sparingly soluble salt $A (O H)_{2}$ (mol. wt. 192.3) is $19.23 g / l i t re$ at $300 K$ . The $p H$ of its saturated solution assuming 80% ionisation at $300 K$ is :

$1.0970$

$12.9030$

$13.2041$

$12.0000$

$S = \frac{19.23}{192.3} mol/litre = 0.1 M$

$∴ [OH^{-}] = \frac{0.1 \times 2 \times 80}{100} = 0.16$
$∴ pOH = 0.7958$
$∴ pH = 13.2041$

Q. The solubility of a sparingly soluble salt A(OH)2​ (mol. wt. 192.3) is 19.23g/litre at 300K . The pH of its saturated solution assuming 80% ionisation at 300K is :

1.0970

12.9030

13.2041

12.0000