The solubility of a saturated solution of calcium fluoride is 2 × 10-4 moles per litre. Its solubility product is

Question

The solubility of a saturated solution of calcium fluoride is 2 × 10-4 moles per litre. Its solubility product is (A) 12 × 10-2 (B) 14 × 10-4 (C) 22 × 10-11 (D) 32 × 10-12

Tardigrade Admin · Accepted Answer

The solubility (s) of saturated solution of

C a F_{2}

is

2 \times 1 0^{- 4} M

.

s C a F_{2} ⇌ s C a^{2 +} + s 2 F^{-}

∴

Solubility product,

K_{s p} = [C a^{2 +}] [F^{-}]^{2}

= S \cdot (2 S)^{2} = 4 S^{3}

= 4 \times (2 \times 1 0^{- 4})^{3}

= 32 \times 1 0^{- 12}

Q. The solubility of a saturated solution of calcium fluoride is $2 \times 1 0^{- 4}$ moles per litre. Its solubility product is

$12 \times 1 0^{- 2}$

$14 \times 1 0^{- 4}$

$22 \times 1 0^{- 11}$

$32 \times 1 0^{- 12}$

The solubility (s) of saturated solution of $C a F_{2}$ is $2 \times 1 0^{- 4} M$ .
$s C a F_{2} ⇌ s C a^{2 +} + s 2 F^{-}$
$∴$ Solubility product, $K_{s p} = [C a^{2 +}] [F^{-}]^{2}$
$= S \cdot (2 S)^{2} = 4 S^{3}$
$= 4 \times (2 \times 1 0^{- 4})^{3}$
$= 32 \times 1 0^{- 12}$

Q. The solubility of a saturated solution of calcium fluoride is 2×10−4 moles per litre. Its solubility product is

12×10−2

14×10−4

22×10−11

32×10−12