The solubility of Ag2S is [Ksp=256× 10-6]:

Question

The solubility of Ag2S is [Ksp=256× 10-6]:  (A)  4× 10-2  (B)  4× 10-3  (C)  0.4× 10-2  (D)  0.4× 10-3

Tardigrade Admin · Accepted Answer

Let solubility of Ag 2 S =x g / L underset textconcentrationAg2S → underset2xAG+ + undersetxS2- Ks p=[ Ag +]2[ S 2-] =(2 x)2(x) =4 x3 Given, Ks p=256 × 10-6 ∴ 256 × 10-6=4 x3 or x=√[3](25 × 10-6/4) =4 × 10-2

Q. The solubility of $A g_{2} S$ is $[K_{s p} = 256 \times 10^{- 6}] :$

$4 \times 10^{- 2}$

$4 \times 10^{- 3}$

$0.4 \times 10^{- 2}$

$0.4 \times 10^{- 3}$

Let solubility of $A g_{2} S = xg / L$
$concentration A g_{2} S \to 2 x A G^{+} + x S^{2 -}$
$K_{s p} = [A g^{+}]^{2} [S^{2 -}]$
$= (2 x)^{2} (x)$
$= 4 x^{3}$
Given, $K_{s p} = 256 \times 1 0^{- 6}$
$∴ 256 \times 1 0^{- 6} = 4 x^{3}$
or $x = 3 \frac{25 \times 1 0 ^{- 6}}{4}$
$= 4 \times 1 0^{- 2}$

Q. The solubility of Ag2​S is [Ksp​=256×10−6]:

4×10−2

4×10−3

0.4×10−2

0.4×10−3

Let solubility of Ag2​S=xg/L concentrationAg2​S​→2xAG+​+xS2−​ Ksp​=[Ag+]2[S2−] =(2x)2(x) =4x3 Given, Ksp​=256×10−6 ∴256×10−6=4x3 or x=3425×10−6​​ =4×10−2

Q. The solubility of $A g_{2} S$ is $[K_{s p} = 256 \times 10^{- 6}] :$

$4 \times 10^{- 2}$

$4 \times 10^{- 3}$

$0.4 \times 10^{- 2}$

$0.4 \times 10^{- 3}$