The solubility in water of a sparingly soluble salt AB2 is 1.0× 10-5mol text L-1 . Its solubility product will be

Question

The solubility in water of a sparingly soluble salt AB2 is 1.0× 10-5mol text L-1 . Its solubility product will be (A)  4× 10-15  (B)  4× 10-10  (C)  1× 10-15  (D)  1× 10-10

Tardigrade Admin · Accepted Answer

Let the solubility =x x=1.0× 10-5mol text L-1 (given) AB2 undersetx mathopA2+ + underset2x mathop2B- Ksp=[A2+][B-]2 Ksp=x× (2x)2 =4x3 Ksp=4× (1× 10-5)3 =4× 10-15

Q. The solubility in water of a sparingly soluble salt $A B_{2}$ is $1.0 \times 10^{- 5} m o l L^{- 1}$ . Its solubility product will be

$4 \times 10^{- 15}$

$4 \times 10^{- 10}$

$1 \times 10^{- 15}$

$1 \times 10^{- 10}$

Let the solubility
$= x$ $x = 1.0 \times 10^{- 5} m o l L^{- 1}$ (given) $A B_{2} x A^{2 +} + 2 x 2 B^{-}$ $K_{s p} = [A^{2 +}] [B^{-}]^{2}$ $K_{s p} = x \times (2 x)^{2}$
$= 4 x^{3}$ $K_{s p} = 4 \times (1 \times 10^{- 5})^{3}$
$= 4 \times 10^{- 15}$

Q. The solubility in water of a sparingly soluble salt AB2​ is 1.0×10−5molL−1 . Its solubility product will be

4×10−15

4×10−10

1×10−15

1×10−10