The slits in Young’s double slit experiment are illuminated by light of wavelength 6000 mathringA. If the path difference at the central bright fringe is zero, what is the path difference for light from the slits at the fourth bright fringe?

Question

The slits in Young’s double slit experiment are illuminated by light of wavelength 6000 mathringA. If the path difference at the central bright fringe is zero, what is the path difference for light from the slits at the fourth bright fringe? (A) 2.4× 10-6m (B) 1.2× 10-6m (C) 10-6m (D)  0.5 × 10-6m

Tardigrade Admin · Accepted Answer

The path difference at the centre is zero. The path difference at the 4th bright fringe = 4λ Here, λ = 6000 × 10-10 m ∴ Path difference = 4 × 6000 × 10-10 = 24 × 10-7 = 2.4 × 10-6 m

Q. The slits in Young’s double slit experiment are illuminated by light of wavelength $6000 \overset{˚}{A}$ . If the path difference at the central bright fringe is zero, what is the path difference for light from the slits at the fourth bright fringe?

$2.4 \times 1 0^{- 6} m$

$1.2 \times 1 0^{- 6} m$

$1 0^{- 6} m$

$0.5 \times 1 0^{- 6} m$

The path difference at the centre is zero.
The path difference at the $4^{t h}$ bright fringe $= 4 λ$
Here, $λ = 6000 \times 1 0^{- 10} m$
$∴$ Path difference $= 4 \times 6000 \times 1 0^{- 10}$
$= 24 \times 1 0^{- 7}$
$= 2.4 \times 1 0^{- 6} m$

Q. The slits in Young’s double slit experiment are illuminated by light of wavelength 6000A˚. If the path difference at the central bright fringe is zero, what is the path difference for light from the slits at the fourth bright fringe?

2.4×10−6m

1.2×10−6m

10−6m

0.5×10−6m