Question

The size of the nucleus of an atom of mass number $A$ is proportional to

• A. $A^{3/4}$
• B. $A^{2/3}$
• C. $A^{1/3}$
• D. $A^{5/3}$

Answer 1

Answer: (C)

Nuclear radius is proportional to $A^{1/3}$,
where $A$ is the mass number of nucleus,
ie, $R\propto A^{1/3}$.
$\Rightarrow R=R_0{A}^{1/3}$.
where $R_0=1.2\times 10^{-15}m$