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Question
Mathematics
The sine of the angle between the vectors i-2j+3k and 2i+j+k is
Q. The sine of the angle between the vectors
i
−
2
j
+
3
k
and
2
i
+
j
+
k
is
4142
182
Vector Algebra
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A
2
7
5
0%
B
7
5
0%
C
1
4
3
50%
D
21
5
50%
Solution:
cos
θ
=
∣
a
∣
∣
b
∣
a
.
b
=
1
+
4
+
9
4
+
1
+
1
2
−
2
+
3
=
84
3
=
28
3
∴
s
in
θ
=
1
−
co
s
2
θ
=
1
−
28
3
=
28
5
=
2
7
5