Question

The $SI$ unit of potential energy is

• A. $kg{\left(m{s}^{-1}\right)}^2$
• B. $kgm{\left(s^{-1}\right)}^3$
• C. $(kgs{)}^{2}m$
• D. $k{g}^{-1}{m}^{-1}{s}^{-1}$

Answer 1

Answer: (A)

Dimension of potential energy = [Energy] $=M{L}^2{T}^{-2}$
$\Rightarrow$ $S.I.$ Unit of potential energy $=kg.m^2{s}^{-2}$
$=kg{\left(m{s}^{-1}\right)}^2$