The SI unit of a physical quantity is pascal-second. The dimensional formula of this quantity will be

Question

The SI unit of a physical quantity is pascal-second. The dimensional formula of this quantity will be (A) [ ML -1 T -1] (B) [ ML -1 T -2] (C) [ ML 2 T -1] (D) [ M -1 L 3 T 0]

Tardigrade Admin · Accepted Answer

Pascal second ( F / A ) t =( MLT -2/ L 2) T = ML -1 T -1

Q. The SI unit of a physical quantity is pascal-second. The dimensional formula of this quantity will be

$[M L^{- 1} T^{- 1}]$

$[M L^{- 1} T^{- 2}]$

$[M L^{2} T^{- 1}]$

$[M^{- 1} L^{3} T^{0}]$

Pascal second
$\frac{F}{A} t = \frac{M L T ^{- 2}}{L ^{2}} T = M L^{- 1} T^{- 1}$

Q. The SI unit of a physical quantity is pascal-second. The dimensional formula of this quantity will be

[ML−1T−1]

[ML−1T−2]

[ML2T−1]

[M−1L3T0]

Pascal second AF​t=L2MLT−2​T=ML−1T−1

$[M L^{- 1} T^{- 1}]$

$[M L^{- 1} T^{- 2}]$

$[M L^{2} T^{- 1}]$

$[M^{- 1} L^{3} T^{0}]$

Pascal second
$\frac{F}{A} t = \frac{M L T ^{- 2}}{L ^{2}} T = M L^{- 1} T^{- 1}$