The shown p-V diagram represents the thermodynamic cycle of an engine, operating with an ideal monoatomic gas. The amount of heat, extracted from the source in a single cycle is

Question

The shown p-V diagram represents the thermodynamic cycle of an engine, operating with an ideal monoatomic gas. The amount of heat, extracted from the source in a single cycle is (A) p0v0 (B) ((13/2))p0v0 (C) ((11/2))p0v0 (D) 4p0v0

Tardigrade Admin · Accepted Answer

Heat is extracted from the source means heat is given to the system (or gas) or Q is positive. This is positive only along the path ABC.
Heat supplied

∴ Q_{A BC} + W_{A BC}

= n C_{v} (T_{f} - T_{i}) +

Area under p-V graph

= n (\frac{3}{2} R) (T_{C} - T_{A}) + 2 p_{0} v_{0}

= \frac{3}{2} (n R T_{C} - n R T_{A}) + 2 p_{0} v_{0}

= \frac{3}{2} (p_{C} V_{C} - p_{A} V_{A}) + 2 p_{0} V_{0}

= \frac{3}{2} (4 p_{0} V_{0} - p_{0} V_{0}) + 2 p_{0} V_{0}

= (\frac{13}{2}) p_{0} V_{0}

Q. The shown p-V diagram represents the thermodynamic cycle of an engine, operating with an ideal monoatomic gas. The amount of heat, extracted from the source in a single cycle is

$p_{0} v_{0}$

$(\frac{13}{2}) p_{0} v_{0}$

$(\frac{11}{2}) p_{0} v_{0}$

$4 p_{0} v_{0}$

Q. The shown p-V diagram represents the thermodynamic cycle of an engine, operating with an ideal monoatomic gas. The amount of heat, extracted from the source in a single cycle is

p0​v0​

(213​)p0​v0​

(211​)p0​v0​

4p0​v0​

$p_{0} v_{0}$

$(\frac{13}{2}) p_{0} v_{0}$

$(\frac{11}{2}) p_{0} v_{0}$

$4 p_{0} v_{0}$