The shortest wavelength present in the Paschen series of spectral lines is

Question

The shortest wavelength present in the Paschen series of spectral lines is (A) 720 nm (B) 790 nm (C) 800 nm (D) 820 nm

Tardigrade Admin · Accepted Answer

The wavelength for Paschen series, (1/λ) = R [(1/32) -(1/n2)] For shortest wavelength n = ∞ ∴ (1/λ) = R [(1/9) -(1/∞2)] = (R/9) ⇒ λ = (9/R) = (9/ 1.097×107) = 8.20 ×10-7 m = 820 nm

Q. The shortest wavelength present in the Paschen series of spectral lines is

$720 nm$

$790 nm$

$800 nm$

$820 nm$

Q. The shortest wavelength present in the Paschen series of spectral lines is

720nm

790nm

800nm

820nm

The wavelength for Paschen series, λ1​=R[321​−n21​] For shortest wavelength n=∞ ∴λ1​=R[91​−∞21​]=9R​ ⇒λ=R9​ =1.097×1079​ =8.20×10−7m =820nm

$720 nm$

$790 nm$

$800 nm$

$820 nm$