The shortest wavelength in the Balmer series is (R = 1.097 × 107 m-1)

Question

The shortest wavelength in the Balmer series is (R = 1.097 × 107 m-1) (A) 200 nm  (B) 256.8 nm  (C) 300 nm  (D) 364.6 nm

Tardigrade Admin · Accepted Answer

Wavelength for Balmer series is (1/λ) = R ((1/22) -(1/n2)) Here, Rydberg's constant R = 1.097 × 107 m-1 ∴ (1/λ) = (4/1.097×107 ) = 364.6 × 10-9 m = 364.6 nm

Q. The shortest wavelength in the Balmer series is $(R = 1.097 \times 1 0^{7} m^{- 1})$

$200 nm$

$256.8 nm$

$300 nm$

$364.6 nm$

Wavelength for Balmer series is
$\frac{1}{λ} = R (\frac{1}{2 ^{2}} - \frac{1}{n ^{2}})$
Here, Rydberg's constant
$R = 1.097 \times 1 0^{7} m^{- 1}$
$∴ \frac{1}{λ} = \frac{4}{1.097 \times 1 0 ^{7}}$
$= 364.6 \times 1 0^{- 9} m$
$= 364.6 nm$

Q. The shortest wavelength in the Balmer series is (R=1.097×107m−1)

200nm

256.8nm

300nm

364.6nm