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Tardigrade
Question
Physics
The shortest wavelength in the Balmer series is (R = 1.097 × 107 m-1)
Q. The shortest wavelength in the Balmer series is
(
R
=
1.097
×
1
0
7
m
−
1
)
11082
194
Atoms
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A
200
nm
14%
B
256.8
nm
40%
C
300
nm
19%
D
364.6
nm
27%
Solution:
Wavelength for Balmer series is
λ
1
=
R
(
2
2
1
−
n
2
1
)
Here, Rydberg's constant
R
=
1.097
×
1
0
7
m
−
1
∴
λ
1
=
1.097
×
1
0
7
4
=
364.6
×
1
0
−
9
m
=
364.6
nm