The shape of water molecule which should be tetrahedral has a bent or distorted tetrahedral shape with a bond angle 104.5°. What could be the reason for this?

Question

The shape of water molecule which should be tetrahedral has a bent or distorted tetrahedral shape with a bond angle 104.5°. What could be the reason for this? (A) lp-lp repulsion is more than lp-bp repulsion (B) lp-bp repulsion is more than lp-lp repulsion (C) lp-lp repulsion is equal to lp-bp repulsion (D) Presence of lone pair does not affect the bond angle

Tardigrade Admin · Accepted Answer

Due to presence of lone pairs, the repulsion is more which changes the bond angle to 104.5°. <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/chemistry/3457600800e65c1fdfd5c4a5c976b930-.png" />

Q. The shape of water molecule which should be tetrahedral has a bent or distorted tetrahedral shape with a bond angle $104. 5^{\circ}$ . What could be the reason for this?

$lp - lp$ repulsion is more than $lp - b p$ repulsion

$lp - b p$ repulsion is more than $lp - lp$ repulsion

$lp - lp$ repulsion is equal to $lp - b p$ repulsion

Presence of lone pair does not affect the bond angle

Due to presence of lone pairs, the repulsion is more which changes the bond angle to $104. 5^{\circ}$ .

Q. The shape of water molecule which should be tetrahedral has a bent or distorted tetrahedral shape with a bond angle 104.5∘. What could be the reason for this?

lp−lp repulsion is more than lp−bp repulsion

lp−bp repulsion is more than lp−lp repulsion

lp−lp repulsion is equal to lp−bp repulsion